bryan334
27.11.2019 •
Mathematics
Write an equation in point -slope form for the line through the given point that has the given slope.
1.) (3,-4); m=6
2.) (4,2); m=-5/3
3.) (0,2); m=4/5
4.) (-2,-7); m=-3/2
5.) (4,0); m=1
6.) (5,-8); m=-3
7.) (-5,2); m=0
8.) (1,-8); m=-1/5
9.) (-6,1); m=2/3
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Ответ:
1. y=6x-22
Step-by-step explanation:
point-slope form equation : y=mx+b
1. (3, -4) m=6
Sub the numbers is
y=-4 / x=3 / m = 6
-4=6*3+b
-4=18+b
b=-22
So your equation would be y=6x-22
2. (4, 2) m=-5/3
sub the numbers into the equation
y=2 / x=4 / m= 5/3
2=4*5/3+b
2=20/3+b
b=8 2/3
so the equation would be
y=-5/3x+8 2/3
3. (0,2) m=4/5
sub the numbers into the equation
2=0*4/5+b
b=2
so the equation would be
y=4/5x+2
4. (-2, -7) -3/2
sub the numbers into the equation
-7=-3/2*-2+b
b=-10
so the equation would be
y= 3/2x-10
5. (4,0) 1
sub the numbers into the equation
0=1*4+b
b=-4
so the equation would be
y=x-4
6. (5,-8) -3
sub the numbers into the equation
-8=5*-3+b
-8=-15+b
b=7
so the equation would be
y=-3x+7
7. (-5, 2) 0
sub the numbers into the equation
2=-5*0+b
b=2
so the equation would be
y=2
8. (1, -8) -1/5
sub the numbers in
-8=1*-1/5+b
b= 7 3/5
so the equation would be
y=-1/5x + 7 3/5
9. (-6,1) 2/3
sub the number in
1=2/3*6+b
b=-3
so the equation would be
y=2/3x-3
Ответ:
1. y+4=6(x-3)
y +4=6x-18
2. y + 2 = -5/3(x-4)
y+2=-5/3x-(-5/3(-4))
3. y=4/5x - 8/5
4. y+7=-3/2x-3
5. y-4=x
6. y+8=-3x +15
7. y-2= 0x
8. y+8= -1/5x-1/5
9. y-1= 2/3x-4
Ответ: