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Mullins4
05.07.2019 •
Mathematics
Write an equation in slope-intercept form for the line that passes through (5,0) and is perpendicular to the line described by y=-5/2x+6
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Ответ:
For this case we have to;
We have that an equation in slope-intercept form is given by:
Where:
m is the slope
b is the cut point with the y axis
Also, by definition, two lines are perpendicular when the product of their slopes is -1. That is:![m_ {1} * m_ {2} = - 1](/tpl/images/0052/4410/9dbd3.png)
We have the line as data:![y_ {1} = \frac {-5} {2} x + 6](/tpl/images/0052/4410/d4230.png)
Then![m_ {1} = \frac {-5} {2}](/tpl/images/0052/4410/ab36a.png)
We found
:
Thus,![y_ {2} = \frac {2} {5} x_ {2} + b_ {2}](/tpl/images/0052/4410/02557.png)
We must find
:
We know that
passes through the point![(x_ {2}, y_ {2}) = (5,0)](/tpl/images/0052/4410/2e305.png)
We substitute the point in the equation of
:
Thus,![y_ {2} = \frac {2} {5} x_ {2} -2](/tpl/images/0052/4410/d17e8.png)
Then the equation in slope-intercept for the line that passes through (5,0) and is perpendicular to the line described by
is: ![y_ {2} = \frac {2} {5} x_ {2} -2](/tpl/images/0052/4410/d17e8.png)
Ответ:
-24
Step-by-step explanation: