Write an equation in slope-intercept form of the line through point P(–3, 6) with slope –2.

         y = - 2x

Step-by-step explanation:

An equation in point-slope form of the line passing through point P(x₁, y₁) with slope m:   y - y₁ = m(x - x₁)

m = -2

P(-3, 6)  ⇒   x₁ = -3,  y₁ = 6

y - 6 = -2(x - (-3))

y - 6 = -2(x + 3)  ←    point-slope form

y - 6 = -2x - 6        {add 6 to both sides}

y = - 2x                 ←    slope-intercept form {intercept=0}

S = ax
It is required to find the value of a which make:
0 ≤ s ≤ 1 when 0 ≤ x ≤ 15
∴ s = 0 when x = 0     ⇒⇒⇒ a = 0 (unacceptable)
or s = 1 when x = 15  ⇒⇒⇒ a = s/x = 1/15

Similarly, t = by
It is required to find the value of b which make:
0 ≤ t ≤ 1 when 0 ≤ y ≤ 60
∴ t = 0 when y = 0     ⇒⇒⇒ b = 0 (unacceptable)
or t = 1 when y = 60  ⇒⇒⇒ b = t/y = 1/60



∴ x = 15s  and  y = 60t



Note: it is not matrix it is determinant