Write an equation in slope-intercept form of the line through point p(–10, 1) with slope –5.

a. y=-5x-49
b. y-1=--5(x+10)
c. y-10=-5(x+1)
d. y= -5x+1

Hello:
the equation is : y = ax+b  a is the slope   : a =-5
     

a = -5         y=-5x+b
the line that passes through (-10,1) :1 = (-5)(-10)+b
b =-49
 the equation is :  y  = -5x-49... ( answer :  A. y=-5x-49 )

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7