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harleymichaelbp74jsq
17.10.2019 •
Mathematics
Write an equation of the line satisfying the given conditions.
through (1,−5); parallel to 5x=6y+7
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Ответ:
ANSWER:
The line equation of required line is 5x – 6y – 35 = 0.
SOLUTION:
Given, line equation is 5x = 6y + 7 and the point is p (1, -5).
We have to find the line equation of a line that is parallel to given line and passing through point p.
First, let us find slope of given line.
5x = 6y + 7
5x – 6y – 7 = 0
We know that, parallel lines will have same slope, so slope of required line is![\frac{5}{6}](/tpl/images/0328/0533/2bbce.png)
Now, we have slope and a point through it.
So, let us find the point slope form of the line i.e![y-y_{1}=m\left(x-x_{1}\right)](/tpl/images/0328/0533/1d69e.png)
Line equation →![y-(-5)=\frac{5}{6}(x-1)](/tpl/images/0328/0533/50baa.png)
6y + 30 = 5x – 5
5x – 6y – 5 – 30 = 0
5x – 6y – 35 = 0
Hence, the line equation of required line is 5x – 6y – 35 = 0.
Ответ:
Solve equation [2] for the variable y
[2] y = 8x + 7
// Plug this in for variable y in equation [1]
[1] 4x - 5•(8x+7) = -9
[1] -36x = 26
// Solve equation [1] for the variable x
[1] 36x = - 26
[1] x = - 13/18
// By now we know this much :
x = -13/18
y = 8x+7
// Use the x value to solve for y
y = 8(-13/18)+7 = 11/9
Solution :
{x,y} = {-13/18,11/9}