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sreeytran
20.12.2019 •
Mathematics
Write an equation with integer solutions of:
x = ±6, y = 0
and
x = 0, y = ±12
a)x2 + y2 + 6 = 0
b)4x2 + y2 + 144 = 0
c)x2 + y2 − 6 = 0
d)4x2 + y2 − 1
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Ответ:
Option 'D' is correct.
Step-by-step explanation:
Since we have given that
x = ±6, y = 0
and x = 0 and y = ±12
And we need an equation which has above as an integer solutions.
So, it becomes,
Consider![4x^2+y^2-144=0](/tpl/images/0427/8888/4db70.png)
Put x = 0, we get
Similarly,
Put y = 0,
Hence, Option 'D' is correct.
Ответ: