Mathematics: Write in simplest radical form: √208

Step-by-step explanation:In circle with center O, By inscribed angle theorem:...

Write in simplest radical form: √208

Ответ:

lukeperry

11.03.2022

$208:2=104\\104:2=52\\52:2=26\\26:2=13\\13:13=1\\\\208=2\cdot2\cdot2\cdot2\cdot13=2^2\cdot2^2\cdot13\\\\\sqrt{208}=\sqrt{2^2\cdot2^2\cdot13}=\sqrt{2^2}\cdot\sqrt{2^2}\cdot\sqrt{13}=2\cdot2\cdot\sqrt{13}=4\sqrt{13}\\\\\ \sqrt{208}=4\sqrt{13}\\\\Used:\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a^2}=a$

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Ответ:

Najibddahir45

29.11.2022

Mathematics

$(180 - 2x)\degree$

Step-by-step explanation:

In circle with center O, $m\angle BCD = x\degree ... (given) \\$

By inscribed angle theorem:

$m\angle BCD= \frac{1}{2} \times m\widehat {BD} \\\therefore x\degree = \frac{1}{2} \times m\widehat {BD} \\\therefore \widehat {BD} = 2x\degree \\\because m\widehat {BCD}+m\widehat {BD}= 360\degree \\(By\: arc\: sum\: postulate\: of\: a \: circle) \\\therefore m\widehat {BCD}+2x\degree = 360\degree \\\therefore m\widehat {BCD} = 360\degree - 2x\degree \\\\\because m\angle BAD = \frac{1}{2}(m\widehat {BCD} - m\widehat {BD}) \\\\\therefore m\angle BAD = \frac{1}{2}(360\degree - 2x\degree - 2x\degree) \\\\\therefore m\angle BAD = \frac{1}{2}(360\degree - 4x\degree ) \\\\\therefore m\angle BAD = \frac{1}{2}\times 2(180\degree - 2x\degree \\\\ \red {\boxed {\bold {\therefore m\angle BAD =(180- 2x)\degree}}} \\\\$

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Write in simplest radical form: √208

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