jonestheproblem5029
05.07.2019 •
Mathematics
Write log3 6 as a logarithm of base 2 a. log base 2 of 3 over log base 2 of 6 b. log base 2 of 6 over log base 2 of 3 c. log base 3 of 2 over log base 6 of 2 d. log base 6 of 2 over log base 3 of 2
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Ответ:
Ответ:
3* (-2) = -6
(-6) + 6 = 0
The goal is for the 'y' coefficients to add to 0.