Lamr
12.05.2021 •
Mathematics
Write the equation in standard form of the circle whose diameter has endpoints of (-2, 4) and (8,-6).
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Ответ:
(x - 3)^2 + (y + 1)^2 = 50.
Step-by-step explanation:
The center of the circle is the midpoint of the diameter
= (-2+8)/2 , (4 - 6)/2
= (3, -1).
The radius^2 can be calculated from one point on the circle ( -2, 4) and the center (3, -1).
The radius^2 = (-2-3)^2 + (4- -1)^2
= 25 + 25 = 50.
So the equation of the circle
is (x - a)^2 + (y - b)^ = r^2 where (a, b) is center and radius = r.
= (x - 3)^2 + (y + 1)^2 = 50
Ответ:
45=20+(x)
Step-by-step explanation: