Write the equation of a circle if its diameter has endpoints (2, 1) and (6, -3).

y = -x + 3

Step-by-step explanation:

Given:

Coordinates are (2, 1) and (6, -3)

y = mx + c

For Coordinate (2, 1)

1 = m(2) + c

1 = 2m + c Eq1

For Coordinate (6, -3)

-3 = m(6) + c

-3 = 6m + c Eq2

From Eq2 - Eq1

6m - 2m = -3 - 1

4m = - 4

m = -1

From eq 1

1 = 2m + c

1 = 2(-1) + c

1 = -2 + c

c = 2 + 1

c = 3

So,

y = mx + c

y = (-1)(x) + 3

y = -x + 3

4 is de factor of 12 n 8

so 4(2x+3)