Write the equation of a circle with the center K(7, 12) and passes through a point J(7, 10) ​

1st: Theatre History

4th Quarter

Upcoming

Due today

Syllabus

Due Sunday

Step-by-step explanation:

1st: Theatre History

4th Quarter

Upcoming

Due today

Syllabus

Due Sunday

Step-by-step explanation:

The center is K(7, 12)

Any point on the circle is connected with the center is the radius.

Since x-coordinates of the center and the given point are same, the radius is the difference of y- coordinates:

The equation:

First, set up a system of equations:

a=b-160

a=2/3c

b=c+92

Then, pick a variable to solve for. I'll start with c.

So, we know that a=b-160 and b=c+92. That means the first equation could be written as a=(c+92)-160. Which simplifies to a=c-68, and a=2/3c, so really 2/3c=c-68. Simplify to 68=1/3c. to get rid of the fraction, multiply both sides by 3.

c=204.

Plug that into the other two equations,

a=2/3(204)

a=136

and

b=(204)+92

b=296