Mathematics: write the equation of a line is perpendicular to the line y=2/3x-4 and passes through the point (6,3) in slope intercept form and point slope form

write the equation of a line is perpendicular to

Ответ:

t779

12.02.2022

Mathematics

y = - $\frac{3}{2}$ x + 12

Step-by-step explanation:

y = $\frac{2}{3}$ x - 4

(6, 3)

y - 3 = - $\frac{3}{2}$ (x - 6)

y = - $\frac{3}{2}$ x + 12

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Ответ:

mel2001love

03.02.2020

Mathematics

Step-by-step explanation:

dy/dt=(y+1)(2√t)

separate the variables and integrating

$\int \frac{dy}{y+1} =\int\ {2\sqrt{t} } \, dt \\log(y+1)=2\frac{t^{\frac{3}{2} } }{\frac{3}{2} } +c\\y+1=e^{\frac{4}{3}t^{\frac{3}{2}+c } } =Ce^{t^{\frac{3}{2} }} \\y=Ce^{t^{\frac{3}{2} } } -1$

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write the equation of a line is perpendicular to the line y=2/3x-4 and passes through the point (6,3) in slope intercept form and point slope form

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