Write the equation of a line perpendicular to 5x+3y=9 and passes through the point (-10,4).

y=3/5x+10

Explanation:

first convert to slope intercept form y=mx+b,   5x+3y=9  that will be y=-5/3x+3, to be perpendicular, the slope has to be an opposite reciprocal so -5/3x has to be 3/5x, then pass through the point (-10,4), the equation will be y=3/5x+10

-50.2

Step-by-step explanation:

2.8-(-5).(-9) + 8 (-1)

2.8 - (-5×-9) - 8

2.8 - 45 - 8

-50.2