Mathematics: Write the equation of the sphere in standard form. x2 + y2 + z2 + 12x − 4y + 2z + 37 = 0 (x+6)2+(y−2)2+(z+1)2=4 find its center and radius.

Write the equation of the sphere in standard

Ответ:

deg12

12.03.2022

The given equation of sphere is

x^2 + y^2 + z^2 + 12x - 4y + 2z + 37 = 0

We have to use completing the square method , and in that method, we have to divide 12x ,-4y,2z by 2, square the results, and add the reult obtained after squaring to both sides. That is

x^2 + y^2 + z^2 + 12x - 4y + 2z+36+4+1 = -37+36+4+1

x^2 +12x+36+ y^2-4y+4 + z^2 +2z+1 = 4

(x+6)^2 +(y-2)^2+(z+1)^2 = 4

So here the center is (-6,2,-1) and radius is 2 .

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Ответ:

gabrielgbobo99

24.06.2020

Mathematics

$tan(14^o)=\frac{30}{x}\\
\\
x=\frac{30}{tan(14^o)}\\
\\
x=\frac{30}{0.25}\\
\\
\boxed{x=7.5}$

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Write the equation of the sphere in standard form. x2 + y2 + z2 + 12x − 4y + 2z + 37 = 0 (x+6)2+(y−2)2+(z+1)2=4 find its center and radius.

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