diamond2738
25.02.2020 •
Mathematics
Write the general equation for the circle that passes through the points (- 5, 0), (0, 4), and (2, 4).
You must include the appropriate sign (+ or -) in your answer. Do not use spaces in your answer.
4x² + 4y² ___x ___y ___ = 0
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Ответ:
[tex]4x^2+4y^2+72x-81y+260=0
Step-by-step explanation:
For the point (-5,0) we have
4*(-5)^2+4*0^2+a*(-5)+b*0+c=0
100-5a+c=0
-5a+c=-100.......(1)
Fro the point (0,4) we have:
4*0^2+4*4^2+a*0+b*4+c=0
64+4b+c=0
4b+c=-64.....(2)
For the point (2,4) we have:
4*4+4*16+2a+4b+c=0
16+64+2a+4b+c=0
2a+4b+c=80.....(3)
(3)-(2):
2a+4b+c-4b-c=80+64
2a=144
a=72
So we have:
-5*72+c=-100
c=260
And from (2) we have
4b+260=-64
b=-81
Ответ:
ax = bx + c (apex)
Step-by-step explanation: