Write the point-slope form of the equation of

Ответ:

zelles9300

16.03.2022

Note: Maybe you either forgot to mention the slope or forgot to mention another point from which the equation of the line passes.

In the later part, I would assume the slope m = 2 as an example.

Please check the explanation.

Step-by-step explanation:

Given

The point (-4, -2)

The point-slope form:

The point-slope form of the line equation is defined as

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line(x₁, y₁) is the point

In our case:

(x₁, y₁) = (-4, -2)

substituting the point (-4, -2) in the point-slope form of the equation of the line

$y-y_1=m\left(x-x_1\right)$

$y-\left(-2\right)=m\left(x-\left(-4\right)\right)$

Therefore, the point-slope form of the equation of the line using the point (-4,-2) will be:

$y-\left(-2\right)=m\left(x-\left(-4\right)\right)$

BONUS!

Example Solving with assuming the slope m = 2

Let suppose the slope m = 2

As we have already got the equation in the point-slope form

$y-\left(-2\right)=m\left(x-\left(-4\right)\right)$

substituting m = 2

$y-\left(-2\right)=2\left(x-\left(-4\right)\right)$

$y+2=2\left(x+4\right)$

Subtract 2 from both sides

$y+2-2=2\left(x+4\right)-2$

y=2x+6

Thus, the point-slope form of the equation of the line using the point (-4,-2) and having slope m = 2.

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