ntrann22
20.07.2019 •
Mathematics
Write the standard equation for a circle with center (−6, −8), that passes through (0, 0)
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Ответ:
Here, (0-[-6])^2 + (0-[-8])^2 = r^2
Find r: 36 + 64 = 100, so r = 10
Then the desired equation is (x+6)^2 + (y+8)^2 = 10^2
Ответ:
Its 5
Step-by-step explanation: