(x^2) +16x+86 = (x+A)^2 +B How do I solve for A - id2168628874010, silasjob09

Question

Mathematics: (x^2) +16x+86 = (x+A)^2 +B How do I solve for A and B

silasjob09 · Accepted Answer

A system of linear inequalities is shown below:

y − x > 0---------(1)

y − 1 > 0---------(2)

Firstly we will graph the inequality (1) as:

we will make a dashed line,

y-x=0

y=x

and the shaded region will be above the line since this inequality could also be represented as:

y>x

so, the points above the line have y-value greater than x values.

Now we will plot the graph of the line,

y-1=0

i.e. y=1

The line will be dashed as the inequality is strict also the line is horizontal and the shaded region will be above the line as the inequality is:

y>1

so, it does not satisfy zero point test.

i.e. on putting (0,0) in the inequality the inequality holds false.

The graph is attached to the answer.

(x^2) +16x+86 = (x+A)^2 +B
How do I solve for A and B