(X^2+x-6)(2x^2+4x) factor completely

Step-by-step explanation:

Lets go ahead and take a step by step approach to solving your problem.

First we must start by factoring .

To do this, we must break the expression into groups! Although I will also provide a definition to help you understand! For we need to find u, v > and which we will group into .

The values we have are... and .

Now we need the factors of 6 which are 1, 2, 3 and 6. We also need the negative factors which you get simply by multiplying the positives by -1 or just reversing them.

Now we need to check for every two factors if u + v = 1.

Therefore .

Now we want to . Which is .

Now we must factor x from .

Lets apply the exponent rule of which means .

Therefore we now have xx - 2x. Lets factor out the common term of x to get x(x - 2).

Now factor 3 out of .

Rewrite 6 as 3 * 2. .

Now factor out the common term of 3 > .

> Factor out the common term of x - 2 > .

Now lets factor .

Apply the previous exponent rule of > > .

Now rewrite 4 as 2 * 2 > .

Now factor out the common term of 2x to get 2x(x + 2).

Combine it all and we get .

Hope this helps!

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Step-by-step explanation: