chem1014
05.12.2020 •
Mathematics
X^4-6x^3+17x^2-28x+20
Solved
Show answers
More tips
- F Food and Cooking How to Make Mayonnaise at Home? Secrets of Homemade Mayonnaise...
- C Computers and Internet Which Phone is Best for Internet Surfing?...
- F Food and Cooking Everything You Need to Know About Pasta...
- C Computers and Internet How to Choose a Monitor?...
- H Horoscopes, Magic, Divination Where Did Tarot Cards Come From?...
- S Style and Beauty How to Make Your Lips Fuller? Ideas and Tips for Beautiful Lips...
- C Computers and Internet How to Learn to Type Fast?...
- A Art and Culture Who Said The Less We Love a Woman, the More She Likes Us ?...
Answers on questions: Mathematics
- M Mathematics A taxi company charges $2.50 plus $1.10 for each mile driven. How much money would you spend if you travel 8 miles...
- M Mathematics What is 10% of 7,518?...
- G German the text is in liveworksheets.com its name is Abitur 2020. 05. Oberstufe Lesen Aufgabe 2. please help...
- C Computers and Technology Describe how microscope can be used to view whats on the slide ...
- E Engineering Can anybody teach me how to make an app with flask and pygame together?...
Ответ:
The expected value of X, E(X), for the given probability distribution is 1.2
Step-by-step explanation:
Mathematical hope (also known as hope, expected value, population means or simply means) expresses the average value of a random phenomenon and is denoted as E(x).
Hope is the sum of the product of the probability of each event and the value of that event. That is, it is the sum of the probability of each possible event multiplied by the frequency of said process, this indicates that if you have a discrete quantitative variable X with "n" possible events x₁, x₂, x₃... xₙ and probabilities P (X = xi) = Pi the mathematical expectation is:
E(x)=x₁*P₁ + x₂*P₂ + x₃*P₃ + ... + xₙ*Pₙ
In this case:
E(x)=x₁*P₁ + x₂*P₂ + x₃*P₃ + x₄*P₄
Being:
x₁: 0 P₁: 0.5x₂: 1P₂:0.1 x₃:2P₃:0.1 x₄: 3P₄: 0.3and replacing:
E(x)= 0* 0.5 + 1* 0.1 + 2*0.1 + 3*0.3
you get:
E(x)= 1.2
The expected value of X, E(X), for the given probability distribution is 1.2