Mathematics: (x+4)²-x²=0 hãy tìm x

(x+4)²-x²=0 hãy tìm x - id4014739293, Izzyfizzy

rodres17

09.11.2021

I hope this helps to :)If so can you mark me as Brainliest please ?

Step-by-step explanation:

Let's solve your equation step-by-step.

$(x+4)^{2} -x^{2} =0$

Step 1: Simplify both sides of the equation.

$(x+4)^{2} -x^{2} =0$

$x^{2} +8x+16+-x^{2} =0$ (Distribute Law)

$(x^{2} + -x^{2})+(8x)+(16)=0$ (Combine Like Terms)

8x+16=0

$8x+16=0\\\\$

Step 2: Subtract 16 from both sides.

$8x+16-16=0-16\\8x=-16$

Step 3: Divide both sides by 8.

$\frac{8x}{8} =\frac{-16}{8}$

x=−2

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slamkam10

23.12.2022

Step-by-step explanation:

2(3-x)-12+4x

(6-2x)-12+4x

-6+4x

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