Lavibookman7934
03.07.2019 •
Mathematics
X+7y=0 and 2x-8y=22 this is solved by using the transitive property
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Ответ:
2x-8y=22 (b)
1st write te 2 equation in terms of x
(a) x+7y=0 , then x= -7y
(b) 2x-8y=22 → 2x = 22 + 8y and x = 22/2 +8y/2 OR x = 11 + 4y
x = 11+4y and x = -7y Then 11 + 4y = -7y
Now we can extract the value of y:
11+4y = -7y
1st Add +7y to each side →11+4y+7y = -7y + 7y
11+ 11y = 0 . Now subtract 11 from both sides :→11+11y -11 = 0-11
11y = -11 and y = - 1
To find the value of x, replace the value of y (= - 1) in any of the given equation and you will find x = 7
Does this helped you?
Ответ:
D
Step-by-step explanation:
10*20=200
200 + 1020= 1220
Works for the first one
20*20=400
400+ 1020=1420
Works for the second one
30*20=600
600+1020=1620
Works for the third one, and all the others one so forth.
You take the number on the left (10, 20, 30, 40, 50, 60, 70) and times it by 20, replacing the x in the equation with the number on the left side of the table. Then you add the number from said equation to result of the multiplication from the first step.