Mathematics: X- 7y = 18 4x + 7y = -30 how can you order a ladder?

X- 7y = 18 4x + 7y = -30 how can you order a ladder?

Ответ:

Aracelys3946

18.04.2022

Mathematics

(a) $9a^{4}b^{10}\left ( 2-3a^6b^5 \right )\left ( 2+3a^6b^5 \right )$

(b) $9a^{4}b^{10}\left ( 2-3a^6b^5 \right )\left ( 2+3a^6b^5 \right )$

Step-by-step explanation:

Given:

$36a^4b^{10}-81a^{16}b^{20}$

To factorise: the given expression using (a) the GCF monomial and (b) the difference of squares

Solution:

(a)

$a^4b^{10}-81a^{16}b^{20}$

GCF of terms $36a^4b^{10}\,,\,81a^{16}b^{20}$ is $9a^{4}b^{10}$

$36a^4b^{10}-81a^{16}b^{20}=9a^{4}b^{10}\left ( 4-9a^{12}b^{10} \right )\\=9a^{4}b^{10}\left [ 2^2-\left ( 3a^6b^5 \right )^2 \right ]\\=9a^{4}b^{10}\left ( 2-3a^6b^5 \right )\left ( 2+3a^6b^5 \right )\,\,\left \{ \because x^2-y^2=(x+y)(x-y) \right \}$

(b)

$36a^4b^{10}-81a^{16}b^{20}=\left ( 6a^2b^5 \right )^2-(9a^8b^{10})^2\\=\left ( 6a^2b^5-9a^8b^{10} \right )\left ( 6a^2b^5+9a^8b^{10} \right )\\=3a^2b^5\left ( 2-3a^6b^5 \right )3a^2b^5\left ( 2+3a^6b^5 \right )\\=9a^4b^{10}\left ( 2-3a^6b^5 \right )\left ( 2+3a^6b^5 \right )$

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X- 7y = 18
4x + 7y = -30
how can you order a ladder?

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