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thanks5640
10.10.2019 •
Mathematics
X-y=11
2x+y=19
equations by elimination
Solved
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Ответ:
x=10, y=-1
(10,-1)
Step-by-step explanation:
x-y=11
2x+y=19
Add these two equations together to eliminate y
x-y=11
2x+y=19
3x = 30
Divide each side by 3
3x/3 = 30/3
x = 10
Now we need to find y
2x+y = 19
2(10) +y = 19
20+y =19
Subtract 20 from each side
20-20 +y = 19-20
y= -1
Ответ:
The correct answer is:
B) Statement 1 and Statement 2 are theorems because they can be proved with the help of appropriate postulates.
Explanation:
Statement 1 is the Line Intersection Theorem. To prove this, we use postulates about having only one plane passing through any 3 noncollinear points. We would choose two points from one line and one point from the second; they would be non-collinear points and be in one plane. This also works choosing the points the opposite way.
Statement 2 is the Point and Line Contained in Plane Theorem. Again, if two lines intersect, we can choose three points to define a plane. We have to prove that both lines are in the plane. We rely on previously proven postulates to do this.