dejahg4530
05.03.2021 •
Mathematics
X, Y and Z are three mutually exclusive events.
P(X) = 0.4, P(Y) = 0.3 and P(
XU Z) = 0.6.
Find:
() P(XUY)
(i) P(Z)
(ii) The probability that none of X, Y or Z
happens
Solved
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Ответ:
√x^2-4
Step-by-step explanation:
Given the expression
√(x+2) * √(x-2)
= √(x+2)(x-2)
Expand
= √x(x)-2x+2x-2(2)
= √x^2-4
Hence the product of the expression will give √x^2-4
For x to be acceptable x^2 - 4 = 0
x^2 = 4
x = ±√4
x = ±2
Acceptable value of x are values that are greater than or equal to ±2