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jmitial
12.12.2020 •
Mathematics
Xavier starts 5 feet away from a motion detector. He then walks away from the detector at a rate of 0.5 ft/sec for 4 seconds. He remains still for 2 seconds, and then walks toward the detector at a rate of −2 ft/sec for 3 seconds. How far in feet is Xavier from the motion detector when he finishes his walk?
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Ответ:
1 foot away from motion detector
Step-by-step explanation:
Given that:
Initial Position = 5 feets away from detector
Distance moved away = 0.5ft/sec for 4 seconds ; distance moved away = 0.5 * 4 = 2 feets
Total distance away = 5 feets + 2 feets = 7 feets
Distance moved towards motion detector :
-2 ft/sec for 3 seconds ;
Distance = speed * time
Distance moved = (-2ft/sec * 3) = - 6 feets
Hence, distance in feets from motion detector :
7 feets - 6feets = 1 feet away from motion detector
Ответ:
(A)
Step-by-step explanation:
Point A is at (-2,4)
Rule of a 180° rotation about the origin: (x,y) --> (-x,-y)
Using the rule, (-2,4) will become (2,-4).
A' should be (2,-4) or Option A.