Y = –3x2 – 12

Axis of symmetry:

Work Shown:

y = -3x^2 - 12 is the same as y = -3x^2 + 0x + (-12)

Compare this to y = ax^2 + bx + c, and we'll find that

a = -3

b = 0

c = -12

Plug the 'a' and 'b' values into the formula below and simplify

h = -b/(2a)

h = -0/(2*(-3))

h = 0

The x coordinate of the vertex is x = 0, so the axis of symmetry is also x = 0.

The axis of symmetry lays perfectly on top of the y axis.

idk

Step-by-step explanation: