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07.03.2020 •
Mathematics
You are interested in determining the effects of a recent coupon promotion on customer purchases at a local grocery store. You sample of 50 customer receipts one day after the coupon is distributed and find the customers' mean spending to be $97.50 with a standard deviation of $4.50. A 90% confidence interval for the population mean would require the use of which critical value: a. t = 1.6766 b. t = 1.2991 c. z = 1.2800 d. z = 1.6450
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Ответ:
(a) t = 1.6766
Step-by-step explanation:
n = 50
degree of freedom = n - 1 = 50 - 1 = 49
confidence level = 90%
The critical value corresponding to 90% confidence level and 49 degrees of freedom is obtained by interpolating between 48 and 50 degrees of freedom (df)
Let the critical value at 49 df be y
dof. critical value
48. 1.677
49. y
50. 1.676
(49 - 48)/(50 - 48) = (y - 1.677)/(1.676 - 1.677)
0.5 × -1×10^-3 = y - 1.677
y - 1.677 = -5×10^-4
y = -5×10^-4 + 1.677 = 1.6765
The closest option is (a)
Ответ:
are there any other details that you didnt include?