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mario65
11.07.2019 •
Mathematics
You are running a fuel economy study. one of the cars you find is blue. it can travel 44 and one half miles on 1 and one fourth gallons of gasoline. another car is red. it can travel 28 and four fifths miles on four fifths gallon of gasoline. what is the unit rate for miles per gallon for each car? which car could travel the greater distance on 1 gallon of gasoline?
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Ответ:
Unit rate of blue car is 35.6 miles/gallon and unit rate of red car is 36 miles/gallon. The red car could travel the greater distance on 1 gallon of gasoline.
Explanation
Unit rate for each car can be calculated using the below formula...
Unit rate = (Distance traveled) / (Amount of gasoline)
For Blue car, distance traveled
and amount of gasoline ![=1 \frac{1}{4}= \frac{5}{4} gallons](/tpl/images/0077/1797/7de68.png)
So, the unit rate for blue car =
÷
=
×
=
miles/gallon
Now for Red car, distance traveled
and amount of gasoline ![= \frac{4}{5} gallons](/tpl/images/0077/1797/a421e.png)
So, the unit rate for red car =
÷
=
×
=
miles/gallon
As the unit rate for red car is greater than the blue car, that means the Red car could travel the greater distance on 1 gallon of gasoline.
Ответ:
9514 1404 393
interest: $63balance: $9063Step-by-step explanation:
After 6 months, the interest accrued is ...
I = Prt
I = $9000·0.014·(6/12) = $63
This is added to the principal to get the balance at that point in time.
$9000 +63 = $9063
__
The interest earned in the first 6 months is $63. The balance after 6 months is $9063.
The compound interest formula will give you the same result for one compounding period. It tells you the balance is ...
A = P(1 +r/n)^(nt)
where n is the number of times interest is compounded in a year (2), and t is the number of years (1/2). For annual rate r = 1.4%, this is ...
A = $9000(1 +0.007)^(2×1/2) = $9000·1.007 = $9063