You are with some repairs at home. you drop a hammer and it hits the
floor at a speed of 8 feet per second. if the acceleration due to gravity (g) is
32 feet/second, how far above the ground (h) was the hammer when you
dropped it? use the formula:
v = 2gh

1 foot.

Step-by-step explanation

That is not the correct formula.  Correct is  V^2 = 2gh  where h = the height

so the equation is:

8^2 = 2*32* h

h = 64/ 64 = 1 foot.

Step-by-step explanation:

In order to be able to solve this problem you just have to clear the formula for height:

V=2gh

So the height from which the hammer is dropped is 1/8 feet.

     Slope of the line passing through (4, 9) and (8, 14) will be .

     Equation of the line →

     Depths of the snow after 0 and 12 hours will be 4 inches and 19 inches respectively.

(a) It's given in the question,

 If we plot 'Time' on x-axis and 'Depth of snow' on y-axis of the graph, (4, 9) and (8, 14) will be two points lying on the straight line.

(b) Slope of the line passing through these points (4, 9) and (8, 14) will be,

    Slope =

    Slope of the line will define the increase in depth of the snow with unit change in time.

Its unit will be inches per hours.

(c). Equation of the line will be,

     d = mh + b

     Here, m = slope of the line

     By substituting the value of 'm' in the equation,

     If the point (4, 9) lies on the line,

     Therefore, equation of the line will be,

     For h = 0,

      inches

     For h = 12 hours,

      inches

  Therefore, slope of the line will be , equation of the line will be and depths of the snow at h = 0 and h = 12 will be 4 inches and 19 inches respectively.

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