You have 12 cards numbered as follows: 2,5,8,10,12,15,18,20,10,7,9,11. What is the probability of choosing an even number, given that it is a multiple of 5? a. 5/12
b. 7/12
c. 1/2
d. 3/5

7/12

Step-by-step explanation:

Simple:

There are 12 numbers in all and only 7 even numbers

Since there are 7 even numbers the probability of rolling an even number is 7/12.

This means that there are 7 outcomes of an even number

Therefore the probability of choosing an even number

=7/12

y=18.51

Step-by-step explanation:

First we must figure out the value of "x". We can do that in the first equation. To find the value of "x" you divide both sides by 20. That will give you the value of "x" which is 2.7. With this information, you can plug in that value into the second equation to get the value of "y". 2(2.7)(y)=100. Multiply 2 and 2.7 to get 5.4. Then divide 5.4 from both sides to get the value of "y" which is around 18.51. I hope this helped.