You have $6000 to invest in stock funds. the first fund pays 5% annual interest. if after a year you have made $380 in interest, how much money did you invest in each account? do not give me answers just an explanation about how to !

Let 
x = amount invested at 5%
y = amount invested at 9%
the amounts are in dollars

We have 6000 total to be split up between the two accounts. This split is likely not to be equal. However, the two values x and y must add up to 6000 because we only have two accounts to choose from. 

So the first equation is 
x+y = 6000
we can solve for y to get 
y = 6000-x
subtract x from both sides



Now onto setting up the second equation
We invest x dollars into the 5% account so we earn 0.05*x dollars in interest for one year from just the 5% account. Similarly, we earn 0.09*y dollars from the 9% account.
In total, we earn 0.05*x + 0.09*y dollars overall. This amount must be set equal to 380 as this is the total amount of interest earned.

So the second equation is
0.05*x + 0.09*y = 380



Now use substitution to solve
0.05*x + 0.09*y = 380
0.05*x + 0.09*( y ) = 380
0.05*x + 0.09*(6000 - x) = 380 replace y with 6000-x
Solve this for x and then use the x value to find y

X intercept is where y=0
that is at x=0
that is also the x intercept

the x and y intecetps are at (0,0)

the end behaviour
as x approaches negative inity, y aproaches positive inifnty
as x approaches positive inifinity, y approaches positiveinifniy