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noahmace
05.05.2020 •
Mathematics
You purchase a car in 2010 for $25,000. The value of the car decreases by 14% annually. What would the value of the car be in 2020?
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Ответ:
-$6,500
Step-by-step explanation:
Here we could , use the arithmetic progression where
T(2020 - 2010) = a + ( n - 1 )d
T10 = a + ( 10 - 1 )d 1
a = $25,000, n = 10 and d = 14% of $25,000 = $3,500 the common difference.
Note since it decreases the common difference d = -$3,500.
Now substitute for the values in the equation above.
T10 = 25,000 + 9 x -3,500
= $25,000 - $31,500
= -$6,500 (deficit )
Ответ: