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crodriguez87
17.07.2020 •
Mathematics
You want to distribute 7 candies to 4 kids. If every kid must receive at least one candy, in how many ways can you do this? (it's not 15)
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Ответ:
20
Step-by-step explanation:
I guess that we want to distribute all the 7 candies between 4 kids
We have 3 options:
first 3, 2, 1 and 1. (the number of candies that each kid gets)
The possible permutations in this case:
if we leave the 3 fixed, the ones do are equal, so the permutations are only given by the change in the kid that gets 2 candies, we have 3 permutations for this.
And for the fixed 3, we have 4 possible places where we can fix it, so the total number of combinations is:
c = 3*4 = 12.
and the second option is (2, 2, 2, 1)
Here the only change is the kid that gets only one candy, we have 4 options in this case:
c = 4.
the third option is (4, 1, 1, 1)
Here the only change is the kid that gets 4 candies, and we have 4 options for this, so we have 4 combinations:
c = 4.
Then the total number of possible combinations is:
C = 12 + 4 + 4 = 20
Ответ:
Step-by-step explanation:
Given
The volume of the pool is![1600\ ft^3](/tpl/images/1223/3825/1ec60.png)
Depth of water is![d=4\ ft](/tpl/images/1223/3825/e5f3a.png)
Suppose A is the base of the pool
This area can be written as