Mathematics: Your friend tossed a fair coin when you weren’t around. she has a habit of messing with you every once in a while, and so there is a 1/3 chance that she will lie to you about the result of the coin toss (report heads as tails and tails as heads), and 2/3 chance that she will tell you the true result of the coin toss. suppose she claims that the coin toss resulted in heads. what’s the probability that she’s lying?

Your friend tossed a fair coin when you weren’t

mbonilla073

02.01.2022

Step-by-step explanation:

Given that your friend tossed a fair coin when you weren’t around.

Let A be the event that she said the outcome is head

B1 = Event she lied and B2 = Event she did not lie

$P(B1) = \frac{1}{3} \\ P(B2) \frac{2}{3}$

P(AB1) = $\frac{1}{2} *\frac{1}{3} =\frac{1}{6}$

P(AB2) = $\frac{2}{3} \frac{1}{2} =\frac{2}{6}$

Required probability = P(B1/A)= $\frac{P(B1A)}{P(B1A)+P(B2A)} \\=\frac{\frac{1}{6} }{\frac{1}{6}+\frac{2}{6}} \\=\frac{1}{3}$

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lame3245

02.01.2023

C) All interior angles are right angles.

Step-by-step explanation:

hope this helps

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