1. A 65 kg student, starting from rest, slides down an 16.2 m high water slide. On the way down, friction does 5700 J of work on him. How fast is he going at the bottom of the slide
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Ответ:
11.94
Explanation:
Remark
Find the Potential Energy at the top.
Givens
m = 65 kg
h = 16.2 m
g = 9.81
PE = 65 * 9.81 * 16.2
PE = 10329.93
The tricky part is what do you do about Friction?
Formula
PE = Friction + KE
Solution
PE = 10329.93 Joules
Friction = 5700 Joules
Find the KE
10329.93 = 5700 + KE
KE = 10329.93 - 5700
KE = 4629.93
Find V from the KE formula
KE = 4629.93
m = 65
KE = 1/2 m v^2
KE = 1/2 65 v^2
4629.93 = 1/2 65 v^2
v^2 = 142.46
v = √142.46
v = 11.94
Ответ:
13 N
Explanation:
From the question,
If two forces act at right angle to each other, Their result force can be calculated using Pythagoras theorem.
R'² = R₁²+R₂²....................... Equation 1
Where R' = Resultant force, R₁ = First force, R₂ = Second force.
Given: R₁ = 12 N, R₂ = 5 N
Substitute these values into equation 1
R'² = 12²+5²
R'² = 144+25
R'² = 169
R' =
R' = 13 N.
Hence the resultant force is 13 N