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shaylawymannnnn
26.05.2021 •
Physics
112 Identifying Types of Reactions:
For each reaction shown, determine whether it is a synthesis, decomposition, combustion, single replacement, or double replacement (precipitation) reaction. Then balance the equation.
___Cu(aq) + ___S ___Cu2S(s)
___Li +___O2 ___Li2O
___C8H18 + ___O2___CO2+ ___H2O
Pb(NO3)2+ __KI ___PbI2 + ___KNO3
___Al + ___ZnCl2 ___Zn + ___AlCl3
___Zr + ___N2 ___ZrN4
___C4H10+ ___O2___CO2+ ___H2O
___NaCl + F2 → NaF + Cl2
___BaCl2 + ___KF ___KCl + __BaF2
___CdO ___Cd + ___O2
___CsCl ___Cs + ___Cl2
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Ответ:
Explanation:
Given that,
Albert and David steal a car and run at
Vt = 90km/hr
Vt = 90×1000/3600 = 25m/s
After 10minutes
t = 10×60 = 600seconds
The police are inform and they started chasing at
Vp = 120km/hr
Vp = 120 × 1000/3600 = 33.33m/s
A. The thief have been running for 1200seconds before the police start
So, the distance between the thief and the police at the start can be determine using
Speed = distance / time taken
So, distance = speed × time taken
d = Vt × t
d = 25 × 600
d = 15,000m
d = 15 km
So, the thief are 15km apart from the thief after 10 minutes
B. Let assume we want to know when police will catch up with the thief.
Now,
The thief is traveling at 25m/s
And police = 33.33m/s
The distance apart is 15,000m
So, let assume the police will catch the thief at distance 'do, then the thief had already travelled 15,000, so the thief will have d - 15000. Note that they will spend the same time in this reference.
So, let find the time the police will traveled 'd'
Speed = distance / time
distance = speed of police × time
d = Vp × t
d = 33.33tequation 1
Also, the thief
Distance = speed of thief × time
15,000-d = 25 × tequation 2
Substitute equation 1 into 2
15,000 - 33.33t = 25t
15,000 = 25t + 33.33t
15,000 = 58.33t
t = 257.14 seconds
So, it will take the police a total of 600second before they were told and the time 257.14 second when they caught the thief.
How long will it have been after the robbery?
Total time after robbery before the car was recovered is
t = 600 + 257.14
t = 857.14 seconds
In Spanish
Dado que,
Albert y David roban un auto y corren a
Vt = 90 km / h
Vt = 90 × 1000/3600 = 25 m / s
Después de 10 minutos
t = 10 × 60 = 600 segundos
La policía está informada y comenzaron a perseguir a
Vp = 120 km / h
Vp = 120 × 1000/3600 = 33.33 m / s
A. El ladrón ha estado corriendo durante 1200 segundos antes de que comience la policía.
Entonces, la distancia entre el ladrón y la policía al inicio se puede determinar usando
Velocidad = distancia / tiempo necesario
Entonces, distancia = velocidad × tiempo tomado
d = Vt × t
d = 25 × 600
d = 15,000m
d = 15 km
Entonces, el ladrón está a 15 km del ladrón después de 10 minutos
B. Supongamos que queremos saber cuándo la policía alcanzará al ladrón.
Ahora,
El ladrón viaja a 25 m / s.
Y policía = 33.33m / s
La distancia es de 15,000m.
Entonces, supongamos que la policía atrapará al ladrón a distancia 'do, entonces el ladrón ya había viajado 15,000, por lo que el ladrón tendrá d - 15000. Tenga en cuenta que pasarán el mismo tiempo en esta referencia.
Entonces, busquemos el tiempo en que la policía viajará 'd'
Velocidad = distancia / tiempo
distancia = velocidad de la policía × tiempo
d = Vp × t
d = 33.33t ecuación 1
Además, el ladrón
Distancia = velocidad del ladrón × tiempo
15,000-d = 25 × t ecuación 2
Sustituye la ecuación 1 en 2
15,000 - 33.33t = 25t
15,000 = 25t + 33.33t
15,000 = 58.33t
t = 257.14 segundos
Entonces, le tomará a la policía un total de 600 segundos antes de que se les diga y el tiempo 257.14 segundos cuando atraparon al ladrón.
¿Cuánto tiempo habrá pasado después del robo?
El tiempo total después del robo antes de recuperar el automóvil es
t = 600 + 257,14
t = 857.14 s