18 Golfer & ball A golfer hits a golf ball, imparting to it an initial speed of 53 m/s directed 27' above the horizontal. Assuming that the
mass of the ball is 41 g and the club and the ball are in contact for 1.0 ms. Find
b) the magnitude of the average force, in Newtons, exerted on the ball by the club:

Correct  a₂ > a₁

Explanation:

Given:

Tony  mass = m₁ = 50 kg

Sam mass = m₂ = 45 kg

According to Newton's second law, the formula for calculating force is:

F = m · a

In this case we have the same force for both

F = m₁ a₁ = m₂ a₂  => a₁ / a₂ = m₂ / m₁ = 45 / 50 = 9 / 10 = 0.9

a₁ = 0.9 a₂  => a₁ = 90% of a₂ => a₂ > a₁

a₂ > a₁

God is with you!!!