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manman1773
30.03.2020 •
Physics
2. The magnetic field inside a 4.0 cm diameter superconducting solenoid varies sinusoidally between 8.0 T and 12.0 T at a frequency of 10 Hz. a. What is the maximum electric field strength at a point 1.5 cm from the solenoid axis?
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Ответ:
The maximum electric field strength is![94.2 \times {10^{ - 2}}\;{\rm{V/m}}](/tpl/images/0571/4126/77698.png)
Explanation:
Substitute 4.0 cm for D
r = D / 2
r = 4 / 2 = 2cm
= 2 × 10⁻²m
Now, according to the question, the expression for the magnetic field is as follows:
B = 10T + 2T sin(2π(10Hz) t )
Now, calculate![\frac{{dB}}{{dt}}](/tpl/images/0571/4126/27abb.png)
Therefore, the electric field expression is as follows:
Substitute 0 for t in the above equation
Now substitute 1.5 cm for r in the above equation
The maximum electric field strength is![94.2 \times {10^{ - 2}}\;{\rm{V/m}}](/tpl/images/0571/4126/77698.png)
Ответ:
Include the area of the rectangle under the line to find displacement for constant acceleration.