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Rainey1664
20.09.2020 •
Physics
3. A model rocket is launched straight upward at 58.8 m/s.
a. How long does it take for the rocket to reach its peak height?
b. what is the total time of flight of the model rocket ?
c. what is the peak height of the rocket from the ground ?
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Ответ:
a). 6 seconds
b). 12 seconds
c). 176.4 meters
Explanation:
a). Equation to be applied to calculate the time taken by the rocket to reach at the peak height,
v = u - gt
where v = final velocity
u = initial velocity = 58.8 m per sec
g = gravitational pull = 9.8 m per sec²
t = duration of the flight
At the peak height,
v = 0
Therefore, 0 = 58.8 - (9.8)(t)
t =![\frac{58.8}{9.8}](/tpl/images/0767/1761/cddbf.png)
= 6 seconds
b). Total time of flight = 2(Time taken to go up)
= 2×6
= 12 sec
c). Formula to get the peak height is,
h = (58.8)6 -![\frac{1}{2}(9.8)(6)^2](/tpl/images/0767/1761/641df.png)
= 352.8 - 176.4
= 176.4 meters
Ответ: