3. How does a wheel and axle increase mechanical advantage? it allows you to apply the force at a greater distance than the resistance

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Ответ:

kaneisha20

16.07.2020

Physics

The percent change in density is (-0.21 %).

Explanation:

Density before raising the temperature:

$\rho_1=\frac{M}{V_1}=\frac{M}{\pi r^2h}$

Temperature of a metal cylinder is raised from 0.0°C to 110°C.

$h'=h+0.22\%\times h=h+0.0022h=1.0022 h$

$\rho_2=\frac{M}{V_2}=\frac{M}{\pi r^2h'}=\frac{M}{\pi r^2(1.0022)h}$

$\text{percentage change}=\frac{rho_2-rho_1}{\rho_1}\times 100$

$\text{percentage change in density}=\frac{\frac{M}{\pi r^2(1.0022)h}-\frac{M}{\pi r^2h}}{\frac{M}{\pi r^2h}}\times 100=-0.21\%$

The negative sign indicates that density had been decreased.

The percent change in density is (-0.21 %).

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