failingschooll0l

10.05.2021 •

Physics

5. Describe one or two behaviors that you're fairly certain you learned through modeling. Do you think the models knew you were watching? Explain.

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Ответ:

nell44

27.07.2022

Physics

(A). The capacitance of the circuit is $2.31\times10^{-6}\ F$ .

(B). The time constant of the circuit is 7.16 sec.

Explanation:

Given that,

Potential = 12.0 V

Internal resistance = 3.10 MΩ

Time = 4.10 s

Voltage = 3.2 V

(A). We need to calculate the capacitance of the circuit

Using formula of capacitance

$V_{C}=V_{0}(e^{\dfrac{-t}{RC}})$

Put the value into the formula

$3.2=12.0e^{\dfrac{-4.10}{3.10\times10^{6}C}}$

$e^{\dfrac{-4.10}{3.10\times10^{6}C}}=0.267$

$\dfrac{-4.10}{3.10\times10^{6}C}=log 0.267$

$C=\dfrac{-4.10}{3.10\times10^{6}\times log0.267}$

$C=0.000002306\ F$

$C=2.31\times10^{-6}\ F$

The capacitance of the circuit is $2.31\times10^{-6}\ F$

(B). We need to calculate the time constant of the circuit

Using formula of time constant

$\tau=R\times C$

Put the value into the formula

$\tau=3.10\times10^{6}\times2.31\times10^{-6}$

$\tau=7.16\ sec$

The time constant of the circuit is 7.16 sec.

Hence, (A). The capacitance of the circuit is $2.31\times10^{-6}\ F$ .

(B). The time constant of the circuit is 7.16 sec.

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5. Describe one or two behaviors that you're fairly certain you learned through modeling. Do you think the models knew you were watching? Explain.​