7. A bob of mass 200 gram is whirled in a horizontal - id720014052107, ykluhredd

Question

Physics: 7. A bob of mass 200 gram is whirled in a horizontal circle of radius 50 cm by a string inclined at 30°. Calculate tension on the string and speed of bob.​

ykluhredd · Accepted Answer

The magnitude of the tension of the in string is 12.04 N.

The given parameters;

mass of the puck, m = 0.085 kg

length of the string, L = 0.72 m

time for a complete revolution, t = 0.45 s

The magnitude of the tension of the in string is determined by calculating the centripetal force on the circular motion;

$F_c = ma_c = \frac{mv^2}{r}$

where;

v is the linear velocity (m/s)

r is the radius of the path (m)

The angular speed is calculated as;

$\omega = \frac{1 \ rev}{0.45 \ s} \times \frac{2\pi \ rad}{1 \ rev} = 13.96 \ rad/s$

The linear velocity is calculated as;

v = ωr

v = 13.96 x 0.72

v = 10.1 m/s

The magnitude of the tension of the in string;

$F_c = \frac{mv^2}{r} = \frac{0.085\times 10.1^2}{0.72} \\\\F_c = 12.04 \ N$

Thus, the magnitude of the tension of the in string is 12.04 N.

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7. A bob of mass 200 gram is whirled in a horizontal circle of radius 50 cm by a string inclined at 30°. Calculate tension on the string and speed of bob.

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7. A bob of mass 200 gram is whirled in a horizontal circle of radius 50 cm by a string inclined at 30°. Calculate tension on the string and speed of bob.​