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princeofpowerjr
12.01.2021 •
Physics
A 0.015 kg marble sliding to the right at 22.5 cm/s on a frictionless surface makes an elastic head-on collision with a 0.015 kg marble moving to the left at 18.0 cm/s. After the collision, the first marble moves to the left at 18.0 cm/s.
A. Find the velocity of the second marble after the collision.
B. Verify your answer by calculating the total kinetic energy before and after the collision.
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Ответ:
Given:
First marble:
Velocity,Second marble,
Velocity,(A)
As we know, the coefficient of restitution will be:
→![e = \frac{v_2-v_1}{u_1-u_2}](/tpl/images/1029/2166/ca6d6.png)
By putting the values,
By applying cross-multiplication,
(B)
The initial K.E:
=![0.5\times 0.015(22.5\times 10^{-2})^2+0.5\times 0.015(18\times 10^{-2})^2](/tpl/images/1029/2166/10dd9.png)
=![6.22\times 10^{-4 \ J](/tpl/images/1029/2166/2a586.png)
The final K.E:
=![0.5\times 0.015(18\times 10^{-2})^2+0.5\times 0.015(22.5\times 10^{-2})^2](/tpl/images/1029/2166/ff849.png)
=![6.22\times 10^{-4 \ J](/tpl/images/1029/2166/2a586.png)
Thus the responses above is right.
Learn more about collision here:
link
Ответ:
Explanation:
mass of first marble![m_1=m=0.015\ kg](/tpl/images/1029/2166/60883.png)
Initial velocity of the first marble![u_1=22.5\ m/s](/tpl/images/1029/2166/6c5d0.png)
considering right side as positive
Mass of second marble
After collision first marble moves to the left with a velocity of 18 cm/s
i.e.![v_1=-18\ cm/s](/tpl/images/1029/2166/beebf.png)
considering
be the velocity of second marble after collision
The Coefficient of restitution is 1 for an elastic collision
Putting values
So, the velocity of the second marble is 22.5 m/s to the right after the collision
(b)Initial kinetic energy =![0.5\times 0.015\times (22.5\times 10^{-2})^2+0.5\times 0.015\times (18\times 10^{-2})^2=6.22\times 10^{-4}\ J](/tpl/images/1029/2166/5b5a6.png)
Final kinetic energy=
Ответ:
I don't know ask other people