alvalynnw

04.04.2020 • 

Physics

A 0.32 kg softball has a velocity of 14 m/s at an angle of 48° below the horizontal just before making contact with the bat. What is the magnitude of the change in momentum of the ball while it is in contact with the bat if the ball leaves the bat with a velocity of (a)16 m/s, vertically downward, and (b)16 m/s, horizontally back toward the pitcher?

Ответ:

dondre54

14.01.2022

Physics

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Explanation:

Let the radius of track required be r.

Centripetal force will be provided by frictional force which will be equal to

m v²/ r

Frictional force = mg x μ

So

m v² /r = mg μ

r = v² / μ g =

  v = 29 km /h = 8.05 m /s

r =( 8.05 x 8.05 ) /( .32 x 9.8 ) = 20.66 m

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