Bangggggg6
13.07.2020 •
Physics
A 10 kg body is suspended by a rope is pulled
by means of a horizontal force to make 60°
by rope to vertical. The horizontal force is
1) 10 kgwt
2) 30 kgwt
3) 10/3 kgwt 4) 30/3 kgwt
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Ответ:
The correct option is;
3) 10·√3 kgwt
Explanation:
The parameters given are;
Mass of body, m = 10 kg
Direction of applied force = Horizontal
Angle of inclination of the rope with the vertical, θ = 60°
The component of the tension in the rope equivalent to the force is given by the relation;
T·sin(θ) = F
The component of the rope tension still under gravitational pull is given by the relation;
T·cos(θ) = m·g
Therefore, we have;
Which gives;
Therefore;
F = tan(θ) × m×g
Where:
g = Acceleration due to gravity
tan(θ) = √3
m = 10 kg
∴ F = 10·√3 × g = 10·√3 kg-wt.
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