organicmemez
04.07.2020 •
Physics
A 110.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 8900.0 kg truck moving in the same direction at 20.000 m/s. The velocity of the car right after the collision is 18.000 m/s to the east.
Required:
a. What is the velocity of the truck right after the collision?
b. What is the change in mechanical energy of the car?
Solved
Show answers
More tips
- C Computers and Internet How to Get Rid of Spam in ICQ?...
- A Art and Culture Who Said The Less We Love a Woman, the More She Likes Us ?...
- F Family and Home How to Get Rid of Your Neighbors?...
- S Society and Politics How Could Nobody Know About the Dead Mountaineers?...
- H Health and Medicine How to Cure Adenoids?...
- H Health and Medicine Why Wearing a Back Brace Can Be Beneficial During Back Strain?...
- S Sport When and Where Will the 2014 World Cup be Held?...
- C Computers and Internet How to Choose a Monitor?...
- H Horoscopes, Magic, Divination Where Did Tarot Cards Come From?...
Answers on questions: Physics
- E English How do people use devices? How do people feel about them? What is the typical opinion people have about devices and learning?...
- H Health Last year, Nora was having problems sleeping at night and her doctor prescribed sleeping pills for one week. Nora took the pills for two nights and then stopped using them....
- M Mathematics Which property allows you to write the expression as 5 − 2i − 1 − 8i? associative commutative distributive identity What is the real part of the difference? What is the...
- M Mathematics I know I’m asking for a lot but y’all are so generous to even tell me the answer! :)...
- M Medicine Sue has Type 1 diabetes, meaning she does not produce any insulin. Her parents give her 1 unit of insulin for every 15 grams of carbohydrate they feed her. Just before her...
Ответ:
Explanation:
Using the law of conservation of momentum which states that the sum of momentum of the bodies before collision is equal to the sum of momentum of bodies after collision.
Momentum = Mass*velocity
BEFORE COLLISION
The momentum of a 110.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction = 110*25 = 2750kgm/s
The momentum of a 8900.0 kg truck with a speed of 20.000 m/s in an easterly direction = 8900*20 = 178000kgm/s
Sum of momentum before collision = 2750 + 178000 = 180,750 kgm/s
AFTER COLLISION
The momentum of the car will be 110*18 = 1980kgm/s
The momentum of the truck = 8900v where v is the velocity of the truck after collision.
Sum of momentum after collision = 1980 + 8900v
Applying the conservation law;
180750 = 1980 + 8900v
8900v = 180750-1980
8900v = 178770
v = 178770/8900
v = 20.09m/s
Velocity of the truck after collision is 20.09m/s
Note that the collision is inelastic i.e the body moves with different velocities after collision
b) The mechanical energy experienced by the bodies is kinetic energy.
Kinetic energy = 1/2mv²
Sum of the Kinetic energy before collision = 1/2(110)*25²+1/2(8900)*20²
= 34375 + 1780000
= 1,814,375Joules
Sum of kinetic energy after collision = 1/2*(110)*18²+1/2(8900)*20.09²
= 17820+1796056.045
= 1,813,876.045Joules
Change in mechanical energy = 1,813,876.045Joules - 1,814,375Joules
= -498.955Joules
Ответ:
Height, h = 8.163 meters
Explanation:
Given the following data;
Mass = 10kg
Potential energy = 800J
We know that acceleration due to gravity is equal to 9.8m/s²
To find the height of the hill;
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
Where,
P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Substituting into the equation, we have;
800 = 10*9.8*h
800 = 98h
Height, h = 800/98
Height, h = 8.163 meters