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sterlingrobinson35
21.04.2020 •
Physics
A 110-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.600 rev/s in 2.00 s
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Ответ:
155 N
Explanation:
We are given following data for a uniform, solid, horizontal disk:
r = 1.5 m
m= 110 kg
t=2 s
w = 0.6
Torque is given by:
т = F*r
=I*α
Solving it for the force exerted on the rope:
F = I*α/r
= (1/2*m*r^2)*(2π*w/t )/r
= (1/2*110*1.5^2)*(2π*0.6/2 )/1.5
= 155 N
Ответ:
B
Explanation:
brachytherapy is wrong