A 1430 kg car speeds up from rest
to 14.0 m/s in 7.00 s. lgnoring
friction, how much power did that
require?
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Ответ:
Power is energy over time
P = E / t
So
P = (m v ^ 2)/ 2 t
P = 20 kW
Ответ:
Explanation:
Given:
Charge = q
Electric field strength =![E_o](/tpl/images/0512/1155/28437.png)
weight of the droplet = mg
The charge is suspended motionless. This is because the electric force on the charge is balanced by the weight of the droplet.
electric force on charged droplet,![F=qE_o](/tpl/images/0512/1155/8c8bc.png)
This is balanced by the weight,![mg](/tpl/images/0512/1155/c761f.png)
Equating the two: