A 1560-kilogram truck moving with a speed of 28.0 m/s runs into the rear end of a 1070-kilogram stationary car. If the collision is completely inelastic, how much kinetic energy is lost in the collision?

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Ответ:

firdausmohammed80

14.02.2020

Physics

$v= \frac{qE}{m}t+u$

Explanation:

Given that, the electron is moving parallel to the electric field.

Then the electron experience a force which is given by,

F=qE

Therefore,

$ma=qE\\a=\frac{qE}{m}$

And q=e, and the acceleration is defines as,

$a=\frac{d^{2}r }{dt^{2} }$

Here, r is the the path traced by an electron.

Now equate the acceleration.

$\frac{d^{2}r }{dt^{2} }=\frac{eE}{m}$

Now integrate both side with respect to t.

$\frac{dr}{dt}= \frac{eE}{m}t+C$

Now, consider at t=0 the initial velocity of electron is u.

$u=\frac{eE}{m}(0)+C\\C=u$

Therefore the velocity of an electron is,

$v= \frac{eE}{m}t+u$

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